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4^x=16 how to find x?
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\[4^x=4^2\] x=2
there are a few ways; but I think they all involve seeing that 16 = 4^2
4^x = 16 ; ln the sides ln(4^x) = ln(16) ; simplify x ln(4) = ln(16) ; /ln(4) x = ln(16)/ln(4) a calculator will be able to solve this format
Using a log to base 4 would probably be simpler than log to base e in this case though.
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