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Mathematics 8 Online
OpenStudy (anonymous):

p2 - 2p + 1

OpenStudy (anonymous):

trinomials

jimthompson5910 (jim_thompson5910):

p^2-2p+1 p^2-p-p+1 p(p-1)-1(p-1) (p-1)(p-1) (p-1)^2

OpenStudy (anonymous):

trinomials

OpenStudy (anonymous):

(p + 1)(p + 1)

OpenStudy (anonymous):

trinomials

OpenStudy (anonymous):

right??

OpenStudy (anonymous):

no wrng dear

jimthompson5910 (jim_thompson5910):

should be (p-1)(p-1), not (p+1)(p+1)

OpenStudy (anonymous):

if u multiply that u will get p2+2p+1 \[\neq\] p2-2p+1

OpenStudy (anonymous):

trinomials

OpenStudy (anonymous):

o but thats not a choice tho??

jimthompson5910 (jim_thompson5910):

what are your answer choices?

OpenStudy (anonymous):

so it will be (p-1)(p-1)

OpenStudy (anonymous):

It's a quadratic (OK, it's a trinomial as well...)

OpenStudy (anonymous):

trinomials

OpenStudy (anonymous):

p - 2)(p + 1) (p - 1)(p + 2) (p + 1)(p + 1) none of the above

OpenStudy (aroub):

none of the above

OpenStudy (anonymous):

trinomials

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the correct answer is : (p-1)(p-1)

jimthompson5910 (jim_thompson5910):

yeah looks like none of the above

OpenStudy (amistre64):

just posting "p2 - 2p + 1" doesnt tell us what needs to be done in order to help you out ..

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