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Mathematics 11 Online
OpenStudy (anonymous):

7.4^7/4 /7.4^4/7

jimthompson5910 (jim_thompson5910):

\[\frac{7.4^{\frac{7}{4}}}{7.4^{\frac{4}{7}}}\] \[7.4^{\frac{7}{4}-\frac{4}{7}}\] \[7.4^{\frac{49}{28}-\frac{16}{49}}\] \[7.4^{\frac{49-16}{28}\] \[7.4^{\frac{33}{28}}\] So \[\frac{7.4^{\frac{7}{4}}}{7.4^{\frac{4}{7}}}=7.4^{\frac{33}{28}}\]

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