Question

7.4^7/4 /7.4^4/7

Answer 1

\[\frac{7.4^{\frac{7}{4}}}{7.4^{\frac{4}{7}}}\]


\[7.4^{\frac{7}{4}-\frac{4}{7}}\]


\[7.4^{\frac{49}{28}-\frac{16}{49}}\]


\[7.4^{\frac{49-16}{28}\]


\[7.4^{\frac{33}{28}}\]


So \[\frac{7.4^{\frac{7}{4}}}{7.4^{\frac{4}{7}}}=7.4^{\frac{33}{28}}\]