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Mathematics 23 Online
OpenStudy (anonymous):

x.(x+y) how we can tell this equation

OpenStudy (anonymous):

Can you explain the question a little more?

OpenStudy (anonymous):

Do you mean that it says x(x+y)?

OpenStudy (anonymous):

x^2+xy

OpenStudy (anonymous):

we will multiply x in the prenthesis as the result we will get : x^2+xy

OpenStudy (anonymous):

x^2+xy

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