Question

Find an equation of the line passing through the two given points (1,-12) and (-2,-3)

Answer 1

y = ax + b is the form of this equation.

a is the slope, found by (y2-y1)/(x2-x1)
b is the y-intercept. found when x = 0.

Answer 2

Slope is (-12-(-3))/1-(-2) = -9/3 = -3

Line with this slope using point (-2,-3) is

y = -3(x-(-2)) -3
y = -3x-9 = -3(x+3)

Answer 3

Where x1, y1 is a known point and m is the gradient.

\[y - y_{1} = m(x - x_{1})\]

\[y - (-12) = -3(x - 1)\]

\[y = -3x - 9\]