Question

Anybody good with word problems?

Answer 1

hit me

Answer 2

me whats the prob

Answer 3

ok, the dimensions of a rectangle are such that its length is 5 in. more than its width. If the length were doubled and if the width were decreased by 2 in., the area would be increased by 162 in squared. What are the length and width of the rectangle?

Answer 4

I'm horrible with these, if I knew the equation to solve I'd be fine lol, the biggest problem is figuring out the equation to solve.

Answer 5

(2(x+5))(x-2)=162

Answer 6

x is the width

Answer 7

and solve for x right?

Answer 8

add 5 to find width

Answer 9

right ok, let me work it and i'll post what i got

Answer 10

I got to 2x^2+6x-20=162 and now I'm stuck again