Mathematics
16 Online
OpenStudy (anonymous):
x-9)^2=49
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OpenStudy (saifoo.khan):
x = 7 + 9
x = 16
OpenStudy (anonymous):
how did you do it?
OpenStudy (saifoo.khan):
Join me! :)
OpenStudy (saifoo.khan):
u htere?
OpenStudy (saifoo.khan):
there*
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OpenStudy (anonymous):
I cant get it to type?
OpenStudy (anonymous):
but I am there
OpenStudy (saifoo.khan):
means?
OpenStudy (anonymous):
im watching!
OpenStudy (saifoo.khan):
O, alright/
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OpenStudy (anonymous):
that was easy lol I recongize that to but I was thinking that I had to use the power but I knew about the sqrt of 49 great
OpenStudy (saifoo.khan):
hmm, :)
OpenStudy (anonymous):
so I was thinking x^2-81=7
OpenStudy (anonymous):
now the next problem that I have is tricky to me...
OpenStudy (saifoo.khan):
x^2 = 7 + 81
x^2 = 88
x = root 88
x = 9.38
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OpenStudy (anonymous):
its a possiblity but I can see your outcome beter...
better*
OpenStudy (saifoo.khan):
Sorry, didnt get that statemnt. :)
OpenStudy (anonymous):
lenght is twice the width find both the lenght and width of 512 yds
OpenStudy (saifoo.khan):
is it a rectangle?
OpenStudy (anonymous):
yes correct!
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OpenStudy (saifoo.khan):
Let width be x
&
Let length be 2x
therefore:
x + x + 2x + 2x = 512
6x = 512
x = 85.33
OpenStudy (saifoo.khan):
Now,
Length = 2x
= 2(85.33)
=170.66
Width = x
= 85.66
OpenStudy (anonymous):
ok I got it I knew that they were going to watn me to round it to a perfect 512 I got it!
OpenStudy (saifoo.khan):
O, ok. cool.
OpenStudy (anonymous):
whats with the girl pic? lol thats hot haha next prob?? r u ready
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OpenStudy (anonymous):
wow
OpenStudy (saifoo.khan):
last week i did someone's online test, passed with 88%!
Scored a A. :D
OpenStudy (anonymous):
nice job!
OpenStudy (anonymous):
too bad you dont have screen flip
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OpenStudy (saifoo.khan):
thnks! :)
OpenStudy (saifoo.khan):
whts Screen Flip?
OpenStudy (anonymous):
(x-9)^2=49
(x-9)^2=7^2
squareroot on the both sides
x-9=7
x=9+7=16
OpenStudy (saifoo.khan):
oye nicK!
hello.
tm kidhr say aayay?
OpenStudy (anonymous):
I havent tried it yet but that one guy was talking about it on his site
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OpenStudy (anonymous):
main ghar se aaya hoon:D
OpenStudy (saifoo.khan):
umm, idk about that site.
OpenStudy (anonymous):
5x^2=10 solve find the x intercetps of 5x^2-10
OpenStudy (anonymous):
saif wtf is this
why didnt u showed me earlier
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OpenStudy (saifoo.khan):
1.4, -1.4
OpenStudy (saifoo.khan):
haha @nick
OpenStudy (anonymous):
5x^2=10 solve find the x intercetps of 5x^2-10=0
y=ax^2
x intercept y= 0
5x^2=0
OpenStudy (anonymous):
not watching now
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OpenStudy (saifoo.khan):
y? :O
OpenStudy (anonymous):
im checking my answer on this one -x^2+4x+3 the vertex
OpenStudy (anonymous):
that is negative x^2+4x+3
OpenStudy (saifoo.khan):
-(x^2+4x+3)
or
-x^2+4x+3
??
OpenStudy (saifoo.khan):
wht answer u got?
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OpenStudy (anonymous):
right but using the formula ax^2+bx+c and -b/2(a)
OpenStudy (anonymous):
then put the outcome in the equation
OpenStudy (anonymous):
I got -2,-1
OpenStudy (saifoo.khan):
checking..
OpenStudy (saifoo.khan):
whts the equation?
-(x^2+4x+3)
or
-x^2+4x+3
??
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OpenStudy (anonymous):
that is we have to use the formula to find the vertex
OpenStudy (anonymous):
the second one
OpenStudy (anonymous):
-x^2+4x+3
OpenStudy (saifoo.khan):
y = 7
x = 2
these are the vertex.
OpenStudy (anonymous):
?? find the vertex, the line of semetry minum or maximum ??
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OpenStudy (saifoo.khan):
vertex is the turning point right?
OpenStudy (anonymous):
yeah that is right
OpenStudy (saifoo.khan):
hmm.
OpenStudy (anonymous):
oh,,, nvm im an idiot did the wrong math
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OpenStudy (anonymous):
the points wold be 2,7
OpenStudy (saifoo.khan):
lol.
OpenStudy (saifoo.khan):
Yea!
OpenStudy (anonymous):
would that be a minumi or max
OpenStudy (anonymous):
max right?
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OpenStudy (anonymous):
what kind of functions would be best used on a scatter plot linear, quadratic or neither
OpenStudy (saifoo.khan):
that will be quadratic.
max & min depend upon the value of a.
If a is +ve so there will be Min point.
If a is -ve so there will be Max point.