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How do you solve cube root -64x^6?
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\[\sqrt[3]{-64^6}\]
What you are trying to do is find a single value that when multiplied by itself 3 times yield your value
It's -64x^6 btw. So would it be.. -4x^2 root x^2?
Heh, right sorry about that
OK, here first, what is the cube root of -64?
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yeah, -4
and you add exponents when multiplying terms with them
so, yes
\[-4*x^2\]
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