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how do you solve root - 9/16 with imaginary numbers?
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\[\sqrt{-9/16}\]
and another question what is root 6 / root 3?
\[\sqrt{\frac {-9}{16}} = \frac{3\sqrt{-1}}{4} = \frac {3i}{4}\]
root(6) = root(3) * root(2) so you can factor out the root 3
therefore root 6 / root 3 = root 2
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