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Vectors. Let A, B and C be collinear and such that AB : BC = 3 : 2. Find AB : BC expressing your answer in terms of integers
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AB : BC = 3:2 2AB = 3BC AC = AB + BC 2/3BC + BC = 5/2BC = -5/2CB Then I don't know what to do :S
what is : ?
nm I think I worked it out 2AB = -5CB so AC : CB = -5:2
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