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In Triangle ABC, Cos B = (9/12) find Sin B.
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SOHCAHTOA/Pythagorus
U know SOHCAHTOA?
cos = Adjacent/Hypotenuse for finding the third side use pythagorus theorem so,AC^2 =AB^2-BC^2 = 12^2-9^2 = 144-81 =63 AC = root 63 AC = 7.9 sinB = Opposite/hypotenuse = 7.9/12
I'm still pretty unfamiliar with SOHCAHTOA.. I am trying to learn it though...
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since cosB=9/12.sinB(opp side/hyp=root 63/12..
Oh, okay, thankyou guys,[;
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