Question

Perimeter of the equilateral triangle ABC is 72 and the perimeter of the isosceles triangle DBC with the base BC=24 is 50. Which is AB + BD?

Answer 1

Since BC=24 is the side of the equilateral triangle ABC, therefore AB=BC=AC=24
The perimeter of isosceles triangle is:
DB+DC+BC=50
But DB=DC
2BD+24=50
2BD=26
BD=13
AB+BD=24+13=37