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Find dx/dy for the equation (1/x^2)+ (1/y^2)=3 .
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x^-2 + y ^-2 = 3 -2x^-3 + -2y^-3* dy/dx = 0 2y^-3* dy/dx = -2x^-3 dy/dx = -2x^-3 / 2y^-3
simplifying dy/dx = -y^3 / x^3
so essentially (y)^3 - ------- (x)^3
ohhh okay
yes
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hope ur curiosity 's been satisfied
Lol. Its been more than satisfied. ;)
okay!!!!
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