Question

If csc x= 4(square root of 3)/3 and cos x<0, how do you evaluate the funstion sin x

Answer 1

sin x = 1 / csc x = 3 / 4(sqrt3)

Answer 2

r u sure cuz the options i was given for sin x are: A) -(sqrt13)/4, B)-(4sqrt13)/13, C) sqrt3/4, D)-sqrt39/13, E)-sqrt39/3