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OpenStudy (anonymous):
If csc x= 4(square root of 3)/3 and cos x<0, how do you evaluate the funstion sin x
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OpenStudy (anonymous):
sin x = 1 / csc x = 3 / 4(sqrt3)
OpenStudy (anonymous):
r u sure cuz the options i was given for sin x are: A) -(sqrt13)/4, B)-(4sqrt13)/13, C) sqrt3/4, D)-sqrt39/13, E)-sqrt39/3
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