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In right triangle DEF, d = 8, e = 10, f = 6. Which is cos D + cos F?
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Ah, this is different. I think D and F are angles to be found
but which angle is the right triangle...I assume E
I think so, there is no picture.
\[D = \sin^{-1}(\frac {8}{10}) , F = \sin^{-1} (\frac {6}{10}) \]
I get sin D + cos F = 1.6
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