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How do I factor 1-x^2
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difference of 2 square factoring (1-x)(1+x)
even isf the x^2 is negative ?
yes, because 1 and x^2 are both perfect squares and they are separated by a - sign. Multiply the factored form that I gave you and you'll get what you started with.
Difference of squares (a^2-b^2) = (a+b)(a-b)
\[(a+b)(a-b) = a(a-b) + b(a-b) = a^2 -ab +ba -b^2 = a^2-b^2\]
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x^2-1 is (x+1)(x-1)
and 1^2 - x^2 is?
U see? 1 = 1^2
dhatraditya How does that make any sence can you just tell me what the answer is ? please.
U have been told the answer 4 times already.
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ab and ba cancel each other. that is why (a+b)(a-b) = a^2-b^2 sorry, I cannot give you the answer, you have to work toward it yourself. I can help guide you to it.
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