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OpenStudy (anonymous):
How would you write z^4+27iz=0 in the form a+bi?
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OpenStudy (anonymous):
z(z^3+27i)=0
OpenStudy (anonymous):
It's already in the form a + bi
OpenStudy (anonymous):
So would it be 1+27i?
OpenStudy (anonymous):
a is z^4 b is 27z so it is in the form a + ib What has 1+27i to do with anything?
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