Question

-3/5b+7+2/5=19

Answer 1

\[-\frac{3}{5}b + 7 + \frac{2}{5} = 19\]
Multiply equation by 5 to eliminate fractions
\[-3b +35 + 2 = 95\]
\[-3b + 37 = 95\]
\[-3b = 58\]
\[b = -\frac{58}{3}\]

Answer 2

so exactly wat is tha answer?

Answer 3

b = -58/3