Question

use the elimination method to find all solutions of the system:
y+x^2=4x
y+4x=16

Answer 1

First, solve for one variable ( usually the easiest)

\[y+4x = 16\] so \[y = 16-4x\]
Then plugin to the other eqaution
\[16-4x+x^2=4x\]
Hence
\[16+x^2 = 8x\]
Leaving the quadratic equation
\[x^2-8x+16 = 0\]
You can solve this by factoring or using the quadratic formula

Answer 2

Thank you!! I was stuck on the very last part.

Answer 3

no problem