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Solve approx to 5th decimal place. 7^(2x+1) = 3^(x+2) x= ?
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For this since they are not the same base, you'll have to just take an arbitrary log of both sides, and rely on the fact that: \[log_ba^k = k(log_b(a))\]
So I'd probably go with either the natural log, or log base 10 since those are ones your calculator will do easily. Then take that log on both sides and bring the exponents down.
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