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Mathematics 22 Online
OpenStudy (anonymous):

Ok I got stuck.... so far I've gotten this far 3x^2y/2*4/xy^3=(3x^2y)(4)/(2)(xy^3) What do I do now?

OpenStudy (anonymous):

is it (xy)^3or x*y^3

OpenStudy (anonymous):

3(4)(1/2)(x^2)(x^-1)(y)(y^-3) 6x/y^2

OpenStudy (anonymous):

and is it (3x)^2y or 3*x^2y

OpenStudy (anonymous):

i don't get it

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