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Mathematics 16 Online
OpenStudy (anonymous):

If P(A)=.3, P(B)=.6, P(A intercepts B) = .18.....does this mean they are NOT Independent because they do not add up? Or do I have it backwards?

OpenStudy (anonymous):

they are independent as P(A intersection B)=P(A)xP(B)

OpenStudy (anonymous):

wonderful..thanks

OpenStudy (anonymous):

np.....................buddy

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