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OpenStudy (anonymous):
If P(A)=.3, P(B)=.6, P(A intercepts B) = .18.....does this mean they are NOT Independent because they do not add up? Or do I have it backwards?
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OpenStudy (anonymous):
they are independent as P(A intersection B)=P(A)xP(B)
OpenStudy (anonymous):
wonderful..thanks
OpenStudy (anonymous):
np.....................buddy
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