Question

√3x+13-5=x

Answer 1

Is this the equation?
\[\sqrt{(3x + 13)} - 5 = x\]

Answer 2

If that is it, then you need to move the 5 to the right hand side of the equation, square both sides, and then solve for x.

Answer 3

\[\sqrt{(3x + 13)} = x + 5\]\[(\sqrt{(3x + 13)})^2 = (x + 5)^2\]\[3x + 13 = x^2 + 7x + 12\]\[0 = x^2 + 7x + 12\]\[0 = (x + 3)(x +4)\]\[x = -4, -3\]

Answer 4

I made a small error. The third line should read

\[3x + 13 = x^2 + 10x + 25\]