Question

x^2 - 4x- 8 =0
How does it work?

Answer 1

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

for ax^2 +bx +c

Answer 2

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Answer 3

thanks for the answers =))))))