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solve x^2+x-110=0
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(x-10)(x+11)=0 x=10 x=-11
x^2+x-110=0 product=-110 sum=+1 factors of 110=1,2,5,10,11,22,55,110 pick numbers from the factors and calculate, so that we get product=-110 sum=+1 here what suits are 11 and -10 so x^2+x-110=0 (x+11)(x-10)=0 x=-11, x=10
x^2+11x-10x-110 x(x+11)-10(x+11) (x-10)(x+11) x=10,x=-11
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