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OpenStudy (anonymous):
solve x^2+2x-35=0
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OpenStudy (anonymous):
x^2+7x-5x-35=0 (x+7)(x-5)=0
OpenStudy (anonymous):
first factor it (x-5)(x+7)=0 then in order for it to =0 one of the two sections must =0 so x-5=0 x+7=0 and solve each of these
OpenStudy (anonymous):
x=-7 x=5
OpenStudy (anonymous):
[-7,5]
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