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Mathematics 14 Online
OpenStudy (anonymous):

solve x^2+2x-35=0

OpenStudy (anonymous):

x^2+7x-5x-35=0 (x+7)(x-5)=0

OpenStudy (anonymous):

first factor it (x-5)(x+7)=0 then in order for it to =0 one of the two sections must =0 so x-5=0 x+7=0 and solve each of these

OpenStudy (anonymous):

x=-7 x=5

OpenStudy (anonymous):

[-7,5]

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