Given two spheres, if the volume of the first sphere is 4/3*3.14 and the volume of the second sphere is 36*3.14 , which is the relation of the second radius to the first?
squared
tripled
doubled
multiplied by a factor of 8/3

Question

Given two spheres, if the volume of the first sphere is 4/3*3.14 and the volume of the second sphere is 36*3.14  , which is the relation of the second radius to the first?
squared
tripled 
doubled
multiplied by a factor of 8/3

anonymous · Answer

the volume of the sphere v=(4/3)pi*r^3
v1=(4/3)pi,  here r1=1
v2=36pi
v2=36pi=(4/3)pi*r^3
36=(4/3)*r^3
36/(4/3)=r^3
             27=r^3
cube root of(27)=r
                      3sqrt3=r=r2   r2 is about three times the r1  ..tripled ans