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Mathematics 19 Online
OpenStudy (anonymous):

Write log6 216=3 in exponential notation

OpenStudy (amistre64):

logB(n) = exp ; therefore, B^exp = n

OpenStudy (anonymous):

?

OpenStudy (amistre64):

look at what you wrote in there: log6(216) = 3 ; now try to conform it to the abstract version logB (n) = exp

OpenStudy (amistre64):

the conversion is then to input the equivalent values into the structure of: B^exp = n

OpenStudy (anonymous):

got it

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