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Mathematics 20 Online
OpenStudy (anonymous):

Another one I get stumped on. I need an answer, please? Thanks! Question attached.

OpenStudy (anonymous):

OpenStudy (anonymous1):

\[\sqrt[6]{64a^9} = \sqrt[6]{64} \sqrt[6]{a^9}\] 64 = 2 to the 6th power, then: \[\sqrt[6]{64a^9} = 2 \sqrt[6]{a^9} = 2a^{9/6} = 2a^{3/2}\]

OpenStudy (anonymous):

It said the answer was incorrect, but thanks anyways.

OpenStudy (anonymous1):

It is correct. What do you mean by "it"?

OpenStudy (anonymous):

My computer program. I posted another.

OpenStudy (anonymous):

But I give you medal for helping me :) Thanks

OpenStudy (anonymous1):

Another form of writing it: \[2\sqrt{a^3}\]

OpenStudy (anonymous):

That might have been right... i have no way to check now though.

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