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Another one I get stumped on. I need an answer, please? Thanks! Question attached.
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\[\sqrt[6]{64a^9} = \sqrt[6]{64} \sqrt[6]{a^9}\] 64 = 2 to the 6th power, then: \[\sqrt[6]{64a^9} = 2 \sqrt[6]{a^9} = 2a^{9/6} = 2a^{3/2}\]
It said the answer was incorrect, but thanks anyways.
It is correct. What do you mean by "it"?
My computer program. I posted another.
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But I give you medal for helping me :) Thanks
Another form of writing it: \[2\sqrt{a^3}\]
That might have been right... i have no way to check now though.
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