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Solve. Write the solution in interval notation.
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\[\left| x+6 \right| \le 12\]
\[ -12 \le x+6 \le 12 \]
-12<x +6<12 -18<x<6
Subtract 6 from all sides
though its the same
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\[\left| x+6 \right|\le12 \leftrightarrow-12\le x+6\le12\leftrightarrow -18\le x \le 6 \] So \[\forall x \in \left[ -18;6 \right], \left| x+6 \right|\le 12\]
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