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OpenStudy (anonymous):
5.How much pure antifreeze must be added to 12 gallons of 10% antifreeze to make a 40% antifreeze solution?
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OpenStudy (amistre64):
anti@1 = 12(.10-.40)/(1-.40) ; just disregard the negative sign maybe
OpenStudy (amistre64):
I got 6 :) but check it
OpenStudy (amistre64):
6 + 12(.10) =? 18(.40) 6 + 1.2 =? 7.2 ; looks good
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