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If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations. x – 3y – 3z = –13 x + 2y – z = –1 2x + 3y + 2z = 0 Answer x – 3y = –13 2x + 3y = 0 x – 3y = –13 –2x – 9y = –10 2x + 3y = 0 4x + 7y = –2 –2x – 9y = –10 4x + 7y = –2
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