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OpenStudy (anonymous):
Another logarithm problem Solve the equation: 256^5x=64^x+4
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OpenStudy (vijay):
u mean 256^(5x)=64^(x+4)
OpenStudy (anonymous):
5xlog (256)=x log (64) + log(4) using log with base 2 5x*8 = 6x + 2 34x = 2 x = 17
OpenStudy (anonymous):
x = 1/17 oops
OpenStudy (anonymous):
yes vijay 256^(5x)=64^(x+4)
OpenStudy (anonymous):
i'm still confused on this answer...
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OpenStudy (vijay):
x = 12/14
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