Question

Five cards are drawn from an ordinary deck of 52 playing cards. What is the probability of getting a full house? (3 of a kind, and 2 of a kind)

Answer 1

LET US BE FIRST CLEAR OF WHAT WE MEAN BY ONE KIND....
I TAKE IT AS SAME SUIT..THAT IS TWO SPADES AND THREE DIAMONDS SAY..OR LIKE THAT...ON THIS BASIS
TOTAL NUMBER OF COMBINATIONS TO DRAW 5 CARDS OUT OF 52 IS 52C5............I
THERE CARE 4 SUITS.WE WANT CARDS OF ANY 2 SUITS ONLY..SO LET US FIRST SELECT 2 SUITS FROM THE 4 AVAILBLE.
THIS CAN BE DONE IN 4C2 WAYS=6 WAYS.................II
NOW ONE COULD BE 2 CARDER AND ANOTHER COULD BE 3 CARDE
SO THE NUMBER OF POSSIBILITIES ARE =2 FROM THE ABOVE 2 SELECTED SUITS......III
THERE ARE 13 CARDS OF EACH SUIT.
NUMBER OF WAYS OF GETTING 2 CARDS OF SAME SUIT IS 13C2.....IV
NUMBER OF WAYS OF GETTING 3 CARDS OF SAME SUIT IS 13C3.....V
SO TOTAL NUMBER OF COMBINATIONS TO GET FULL HOUSE ARE II*III*IV*V
SUCCESSFULL COMBINATIONS =6*2*13C2*13C3
PROBABILITY=6*2*13C2*13C3/52C5

Answer 2

Thank you so much for your help! :)

Answer 3

\[\Huge \color\red {U.r.WELCOME!.. :)}\]

Answer 4

Can i ask wht does "5369855" stands for?

Answer 5

it's my name in letters :) like ABC = 1

Answer 6

OIC, Cool.

Hard to guess.
lol.

Answer 7

Yep :) No one understands it haha

Answer 8

Lol.

Answer 9

:D