Question

Find the center and the radius
x^2+y^2=16

Answer 1

I got 0.0 and 4

Answer 2

yes

Answer 3

The equation of a circle centered in (a;b) with radius r is
\[(x-a)^2+(y-b)^2=r^2\]
So it's a circle centered in (0;0) and of radius 4.