Question

Please check
x^2-y^2=4
x+y=2

I got x=8+4y^2+y^4
y=-2-y^2

Answer 1

\[\{\{x\to 2,y\to 0\}\} \]

Answer 2

so (2,0) ?

Answer 3

Yes, written as an "ordered pair"

Answer 4

Thank you.