Question

Find the zeros of y=x^2-2x-8 and the equation of axis of symmetry

Answer 1

whoops

Answer 2

lets try that again. axis of symmetry is
\[x=-\frac{b}{2a}\] in this case you get
\[x=-\frac{-2}{2\times 1}=1\]

Answer 3

to get zeros factor as
\[(x-4)(x+2)=0\]
\[x=4\] or
\[x=-2\]

Answer 4

you can see that the zeros are equidistant from the axis of symmetry. that is
\[|4-1|=3\] and \[|-2-1|=3\]

Answer 5

But would it be x or y that equals to 1 ? Im confused .