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What is the vertex of the graph y=x^2+3x-4
V(-b/2a; -delta/4a) a=1, b=3 ,c=-4 delta = b^2 - 4ac -b/2a = -3/2 -delta = 4ac - b^2 = -16 - 9 = -25 -delta/4a = -25/4 The vertex is V(-3/2 ; -25/4)
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