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x^2-4x+___=(__)^2 what numbers would make this true ?
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You need to do whats called completing the square. when you have a quadratic equation in the form: \[x^2+bx+c\] for it to be a square, c must be: \[c = (\frac{b}{2})^2\]
+4; this would give (x-2)^2
Would the 2 be negative or positive ?
negative. (x-2)(x-2)=x^2-4x+4
- Thanks , alot .
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no prob :)
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