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OpenStudy (anonymous):
Find the probability that a randomly chosen point in the figures lies in the shaded region.
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OpenStudy (anonymous):
OpenStudy (anonymous):
et probability = shaded area / total area. P=(144-36pi)/144 P=1-pi/4
OpenStudy (anonymous):
Ssqr = 12*12=144 Scrcl = pi*6*6 P(point in circle) =(12*12)/(pi*6*6)
OpenStudy (anonymous):
thnk you both
OpenStudy (anonymous):
Actualy use 36pi/144
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OpenStudy (anonymous):
can either of you help me on my next one?
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