Question

Find the x-intercepts of the parabola with vertex (6,-5) and y-intercepts (0,175). Write the answer in this form: (x1,y1),(x2,y2).

Answer 1

help? :(

Answer 2

1) (y - k)^2 = 4a(x - h)
2) (y- -5)^2 = 4a(x-6)
3) (175+5)^2=4a(0-6)
4) (180)^2 = 4a (-6)
5) 32400 = 4a(-6)
6) -5400 = 4a
7) -1350=a
8)(y +5)^2 = 4 * -1350(x - 6) at this point it is easier to graph it on a calculator
set it as : y= [+/- square root of -5400(x - 6)] -5
(b/c it could be either pos. or neg.)

Answer 3

w/o a calc : 5^2 = -5400(x-6) .....remember y=0 at an x intercept
25/-5400= x-6
-.0046=x-6
5.9954=x