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for the curve what is the equation of the tangent of the line of f(x) = root (x-5) when x=9
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Have you tried drawing an x,y table to graph what root(x - 5) looks like?
no
(9,2) is the point. this will help us find the equation once we have the slope. f'(x) = .5(x-5)^(-.5) f'(9) = .25 now that you have the slope and a point. you can easily find the equation
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