Can anyone tell me how to solve the following logarithm: 7 ^ log7 12?

Question

anonymous · Answer

can you rewrite your question using the equation button below?

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anonymous · Answer

$$7^{\log _{7}12}$$

anonymous · Answer

okay.
one of the logarthmic properties is 
$$b^{\log_b x} = x$$ 
apply that here and tell me what the answer is.

anonymous · Answer

Okay, I get 12, am I reading this wrong?

anonymous · Answer

12 is right

anonymous · Answer

Thanks so much!!! I'm having difficulty with another question: 

$$\log _{3} (2x-1)^{3}$$
Somehow I ended up with $$2^{2/3}$$ but I have a feeling I'm wrong.

anonymous · Answer

what are you supposed to do with the log? is it equal to something?
how did you end up with 2^2/3 anyway? what is x?