Question

Can anyone tell me how to solve the following logarithm: 7 ^ log7 12?

Answer 1

can you rewrite your question using the equation button below?

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Answer 2

\[7^{\log _{7}12}\]

Answer 3

okay.
one of the logarthmic properties is
\[b^{\log_b x} = x\]
apply that here and tell me what the answer is.

Answer 4

Okay, I get 12, am I reading this wrong?

Answer 5

12 is right

Answer 6

Thanks so much!!! I'm having difficulty with another question:

\[\log _{3} (2x-1)^{3}\]
Somehow I ended up with \[2^{2/3}\] but I have a feeling I'm wrong.

Answer 7

what are you supposed to do with the log? is it equal to something?
how did you end up with 2^2/3 anyway? what is x?