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Mathematics 15 Online
OpenStudy (anonymous):

x^2-6x+5=0

OpenStudy (anonymous):

5 and 1

OpenStudy (anonymous):

x=1 , x=5

OpenStudy (anonymous):

x^2-6x+5=0 (x-1)(x-5)=0 x-1=0 x=1 x-5=0 x=5

OpenStudy (anonymous):

x^2-5x-x+5=0 x(x-5)-1(x-5)=0 (x-1)(x-5)=0 x=1,5

OpenStudy (anonymous):

but it could be only one #

OpenStudy (anonymous):

there are two answers tho

OpenStudy (anonymous):

x^2-5x-x+5 = 0 x(x-5)-1(x-5) (x-1)(x-5) x=1,x=5

OpenStudy (anonymous):

i see thanks i read it wrong

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