Question

6x(y^2z) if x=1/2, y=-1, z=2

Answer 1

-6

Answer 2

so -1^2 stays a negative

Answer 3

correct

Answer 4

I have 6.
\[6(1/2)(-1)^{2}(2)\]

Answer 5

3(1*2)= 6 lolz

Answer 6

The -1 when squared becomes 1.

Answer 7

see thats whats messing me up

Answer 8

The problem has y as a whole squared, not -(y^2).

Answer 9

(-1)*(-1) = 1

Answer 10

osirisis is right, don't listen to me :P

Answer 11

osirsis is completely right !!