Question

Question
A canoe can go 24 km downstream in 3 hours. The return trip takes 4 hours. What is the speed of the current?

Answer 1

boat speed =a
current=c
3(a+c)=24
4(a-c)=24

Answer 2

3a+3c=24
4a-4c=24
solve for a and c

Answer 3

so i am supposed to add these two equations together im lost??

Answer 4

How would you solve system of equations

Answer 5

PEMDAS- would i use that??

Answer 6

Easy jst divide by 3 both sidez 3(a+c)=24
yu will get a+c=8
Then divide by 4 both sidez 4(a-c)=24 yu will get a-c=6


a+c=8
a-c=6
then yu will get 2a=14
then a=7 c=1

Answer 7

Here is a step by step solution:

Let Vd = speed downstream
Vu = speed upstream
Vc = speed of the canoe
Vs = speed of the stream

Going downstream we know Vd = 24/3 = 8.
Going upstream we know Vu = 24/4 = 6.

Going downstream we are going in the direction of Vs so:
Vd = Vs + Vc or 8=Vs + Vc

Going upstream we are going against the direction of Vs so:
Vu =Vc - Vs or 6 = Vc - Vs

So we have two equations in two unknowns. Solve them:

Vc+Vs = 8
Vc-Vs = 6
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2Vc = 14
Vc = 7
Vs = 1