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OpenStudy (anonymous):
what would the equation be for this? Find the first 3 terms of the sequence that has a1 = 2, a2 = 6, and an = 3a(n − 1)a(n − 2).
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OpenStudy (anonymous):
\[a_3 = 2 \times 6 \times 3 = 36\]
OpenStudy (anonymous):
so this is the formula for a_n? \[a_n = 3a_{n-1}*a_{n-2}\]
OpenStudy (anonymous):
thank you both!
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