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OpenStudy (anonymous):
OpenStudy (anonymous):
its inverted
OpenStudy (anonymous):
OpenStudy (anonymous):
its .2
OpenStudy (anonymous):
can you help me understand why?
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OpenStudy (anonymous):
sure
OpenStudy (anonymous):
y=ax^2 just derivate it so that u get the value of dy/dx. which is in terms of a
so substitute the given values in y=ax^2 .
and b is nothing but the slope of the line in standard form
OpenStudy (anonymous):
i got a = y'/2x???
OpenStudy (anonymous):
also a=y/x^2 so a=100/1000000(given values)
OpenStudy (anonymous):
how do we use a to find b?
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OpenStudy (anonymous):
dy/dx=2ax r8t? and b=dy/dx ie slope in standard form dude!!!!!!
OpenStudy (anonymous):
so 2ax = b.... what do I use for x?
OpenStudy (anonymous):
no jst find dy/dx which is .2 and this is equal to b
OpenStudy (anonymous):
but what happens to the x in 2aX = b?
OpenStudy (anonymous):
x=1000 its given
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OpenStudy (anonymous):
so 2 x 1000 x .1?
OpenStudy (anonymous):
since after that its straight line sloppe remains constant
OpenStudy (anonymous):
a=100/1000*1000=.0001
OpenStudy (anonymous):
right ok got it thanks so much
OpenStudy (anonymous):
do you think you could answer my last question?
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OpenStudy (anonymous):
finally hughhh!!!!!!
OpenStudy (anonymous):
sorry. not everyone is great at math.
OpenStudy (anonymous):
it's late and it's summer.
OpenStudy (anonymous):
nor i m i dude sometimes its just like that
take it easy dude
OpenStudy (anonymous):
sorry, it's just that I get frustrated when I don't understand things right away. and typing is much harder than having an actual conversation when trying to get help. I appreciate it though.