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Solve: x^4 + 4x^3 - x - 4 = 0
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x^3(x+4)-1(x+4)=0 (x^3-1)(x+3)=0 so x=1,-3
the real zeros are 4 and -1 (from the graph of it), plus there are two complex zeros. :/
Yeap, I havenot considered complex numbers here.........
sorry (x+4)
so x=-4
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Oh, right. But I still need the complex zeros...
-0.5+0.87i -0.5-0.87i
Might you have the exact number/fraction for that .87?
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