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Find the area of the shaded portion. A=
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shaded area = quad area - area of circle/3
Draw a line bisecting the 120 degree angle such that it forms 2 right triangles. half of 120 is 60 So each right triangle is a special 30-60-90 right triangle with sides 6,6sqrt3,12 The area of each of these triangles is (6*6sqrt3)/2 thus area of both is 36sqrt3. Then subtract area of sector which is one-third of circle (pi*6^2)/3 A = 36sqrt3 - 12pi
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